2x^2-48=1008

Solution for 2x^2-48=1008 equation:

2x^2-48=1008

We move all terms to the left:

2x^2-48-(1008)=0

We add all the numbers together, and all the variables

2x^2-1056=0

a = 2; b = 0; c = -1056;
Δ = b2-4ac
Δ = 02-4·2·(-1056)
Δ = 8448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8448}=\sqrt{256*33}=\sqrt{256}*\sqrt{33}=16\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{33}}{2*2}=\frac{0-16\sqrt{33}}{4}
=-\frac{16\sqrt{33}}{4}
=-4\sqrt{33}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{33}}{2*2}=\frac{0+16\sqrt{33}}{4}
=\frac{16\sqrt{33}}{4}
=4\sqrt{33}
$